At some point in the field, a force of 4 * 10-3 N acts on a charge of 10-7 C. Find the field strength at this point

| September 4, 2021 | education

At some point in the field, a force of 4 * 10-3 N acts on a charge of 10-7 C. Find the field strength at this point and determine the charge that creates the field if the point is 0.3 m away from it.

To calculate the value of the intensity at a specified point of the field and the magnitude of the charge that creates the field, we apply the formulas: E = F / q1 and E = k * q / r ^ 2, whence we express: q = E * r ^ 2 / k.

Variables and constants: F – force acting on a given charge (F = 4 * 10 ^ -3 N); q1 – charge at some point (q1 = 10-7 C); r is the distance to the desired charge (r = 0.3 m); k (aspect ratio) = 9 * 10 ^ 9 m / F.

1) Field strength: E = F / q1 = 4 * 10 ^ -3 / 10 ^ -7 = 40 * 10 ^ 3 V / m = 40 kV / m.

2) The charge that creates the field: q = E * r ^ 2 / k = 40 * 10 ^ 3 * 0.32 / (9 * 109) = 4 * 10 ^ -7 Cl.

Answer: The field strength is 40 kV / m; the charge is 4 * 10-7 C.



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