At the base of a straight parallelepiped lies a rhombus with a side of 4 and an acute angle of 30 degrees.
At the base of a straight parallelepiped lies a rhombus with a side of 4 and an acute angle of 30 degrees. Find the volume of a parallelepiped if the diagonal of its side face is 5.
As you know, the volume of a parallelepiped is equal to the product of the area of the base and the height. Let’s find the area of the base.
The height of a rhombus is equal to the product of its side and the sine of an acute angle. In this case, the height will be equal to:
4 * 1/2 = 2.
This means that the base area of this parallelepiped is:
S = 4 * 2 = 8.
The side face of this parallelepiped is a rectangle with a length of 4 and a diagonal of 5. This means the second side of the side face, that is, the height of the parallelepiped will be:
х² = 5² – 4²,
x² = 25 – 16,
x² = 9,
x = 3.
Thus, the volume of the parallelepiped is:
V = 8 * 3 = 24.