At the base of a straight prism there is a right-angled triangle, the legs of which are 6 cm and 8 cm.
At the base of a straight prism there is a right-angled triangle, the legs of which are 6 cm and 8 cm. Lateral edge of the prism 12. Find the total surface area of the prism and its volume.
Since there is a right-angled triangle at the base of the prism, its area will be equal to:
Savs = AB * BC / 2 = 8 * 6/2 = 24 cm2.
Let’s define the volume of the prism.
Vpr = Sbn * АА1 = 24 * 12 = 288 cm3.
In a right-angled triangle ABC, according to the Pythagorean theorem, we determine the length of the hypotenuse AC.
AC ^ 2 = AB ^ 2 + BC ^ 2 = 64 + 36 = 100.
AC = 10 cm.
Since the prism is straight, the side faces of the prism are rectangles, then: Sside = P * AA1, where P is the perimeter of the base of the prism.
P = AB + BC + AC = 8 + 6 + 10 = 24 cm.
Side = 24 * 12 = 288 cm2.
Then Spol = 2 * Sb + S side = 2 * 24 + 288 = 336 cm2.
Answer: The volume of the prism is 288 cm3, the total surface area is 336 cm2.