At the base of the house, the water pressure in the water supply is p = 500 kPa. At a height of h = 15 m

At the base of the house, the water pressure in the water supply is p = 500 kPa. At a height of h = 15 m on the fourth floor, the tap water flows out under pressure …

Given:

P = 500 kPa = 500000 Pascal – water pressure in the water supply system at the base of the house;

h = 15 meters – the height of the fourth floor of the house;

g = 10 Newton / kilogram – acceleration of gravity;

ro = 1000 kilograms / cubic meter – density of water.

It is required to determine P1 (Pascal) – at what pressure water flows out of the tap on the fourth floor.

Let’s find the total height of the house:

h0 = P / (ro * g) = 500000 / (10 * 1000) = 500000/10000 = 50 meters.

Then, on the fourth floor, the water column is:

h1 = h0 – h = 50 – 15 = 35 meters.

The pressure on the fourth floor will be equal to:

P1 = ro * g * h1 = 1000 * 10 * 35 = 10000 * 35 = 350,000 Pascal.

Answer: on the fourth floor of the house, water flows out at a pressure equal to 350,000 Pascals.