At the base of the pyramid lies a right-angled triangle with legs 10 and 24, all the side faces of the pyramid are inclined

At the base of the pyramid lies a right-angled triangle with legs 10 and 24, all the side faces of the pyramid are inclined to the base plane at an angle of 60 degrees find the area of the side surface of the pyramid

In this problem, the base is considered as the sum of the projections of the side faces onto the base plane. Therefore, the task is simplified.
Since the angle of inclination is the same for all faces, we can create the following formula:
Sboc = Sosn / cos (60) = 2 * Sosn = 2 * (1/2) * 10 * 24 = 240;
Answer: 240.