At the bottom of the aquarium is a stone completely submerged in water and in a state of equilibrium.

At the bottom of the aquarium is a stone completely submerged in water and in a state of equilibrium. Will the Archimedes force acting on the stone change if water is added to the aquarium? Will the pressure on the bottom of the aquarium change?

The Archimedean force acting on a body in water is calculated by the formula:

Aarchimedes = ro-liquid * Vbody * g, where: ro-liquid is the density of the liquid, Vbody is the volume of the body immersed in the liquid, g is the acceleration of gravity. Since, according to the condition of the problem, adding water to the aquarium, we will not change either the density or the volume of the body, the Archimedean force will not change.

The water pressure at the bottom of the aquarium is calculated using the formula:

Pfluid = rofluid * g * H, where: rofluid is the density of the liquid, g is the acceleration of gravity, H is the height of the liquid column. By adding water to the aquarium, we will increase the height of the liquid column, respectively, the force of water pressure on the bottom of the aquarium will also increase.

Answer: Archimedes’ force acting on the stone will not change. The water pressure on the bottom of the aquarium will increase.