At the end of the line segment AB lie on opposite sides of the line L. The distance from point A

At the end of the line segment AB lie on opposite sides of the line L. The distance from point A to line L is 24 cm, and the distance from point B to line L is 30 cm. Find the distance from the middle of line segment AB to line L.

Let us draw a straight line BM parallel to the straight line L and a straight line AM, perpendicular to the BM.

The length of the segment is DM = CB = 30 cm.

The length of the segment AM = AD + DМ = 24 + 30 = 54 cm.

Since point H is the middle of CD, then the segment РK is the middle line of the triangle ABM, then РK = AM / 2 = 54/2 = 27 cm.

CB = НР + PK.

НР = CB – РK = 30 – 27 = 3 cm.

Answer: From the middle of AB to straight L 3 cm.