At the ends of a conductor with a resistance of 220 ohms, a voltage of 110V is created.

At the ends of a conductor with a resistance of 220 ohms, a voltage of 110V is created. Determine the amount of electricity transferred through the cross-section of the conductor in 40 minutes

R = 220 ohms.

U = 110 V.

t = 40 min = 2400 s.

Q -?

The current strength I is called a scalar physical quantity, which shows what electric charge Q is transferred through the cross-section of the conductor per unit of time t: I = Q / t.

The value of the current I will be expressed according to Ohm’s law for the section of the circuit: I = U / R, where U is the voltage at the ends of the conductor, R is the resistance of the conductor.

Q / t = U / R.

Q = U * t / R.

Q = 110 V * 2400 s / 220 Ohm = 1200 Cl.

Answer: electricity Q = 1200 C was transferred through the cross-section of the conductor.