At the ends of the thread, thrown over a fixed block, two weights are suspended: on the left, weighing 50 g

At the ends of the thread, thrown over a fixed block, two weights are suspended: on the left, weighing 50 g. And with the right weight 100g. How long will it take for the right weight to drop 5 cm?

Given:

m1 = 50 grams = 0.05 kilograms – the mass of the left weight;

m2 = 100 grams = 0.1 kilograms – weight of the right weight;

g = 10 N / kg – acceleration of gravity;

S = 5 centimeters = 0.05 meters.

It is required to determine after what time t (seconds) the right weight will fall to the distance S.

Let’s find the acceleration with which the system of bodies moves. From Newton’s second law:

m2 * g – T = m2 * a, where T is the tension force of the thread.

T – m1 * g = m1 * a;

T = m1 * a + m1 * g;

m2 * g – m1 * a – m1 * g = m2 * a;

m2 * g – m1 * g = m2 * a + m1 * a;

g * (m2 – m1) = a * (m2 + m1);

a = g * (m2 – m1) / (m2 + m1) = 10 * (0.1 – 0.05) / (0.1 + 0.05) =

= 10 * 0.05 / 0.15 = 0.5 / 0.15 = 3.3 m / s ^ 2.

Then the time will be equal to:

t = (2 * S / a) ^ 0.5 = (2 * 0.05 / 3.3) ^ 0.5 = (0.1 / 3.3) ^ 0.5 = 0.03 ^ 0, 5 = 0.2 seconds.

Answer: The right weight will drop 5 centimeters in 0.2 seconds.