At the same height, there are aluminum and lead balls of the same radius, which of them has a higher potential energy

Potential energy: Ep = mgh, where m is body mass, g is gravitational acceleration, h is body height.
Ep1 = m1gh is the potential energy of the lead ball.
Ep2 = m2gh-potential energy of the aluminum ball.
For a lead ball: m1 = ρ1 * V, where ρ1 is the density of lead (ρ1 = 11300 kg / m ^ 3), V is the volume of the ball.
For an aluminum ball: m2 = ρ2 * V, where ρ1 is the density of aluminum (ρ2 = 2700 kg / m ^ 3), V is the volume of the ball.
Ep1 / Ep2 = ρ1 * V * g * h / (ρ2 * V * g * h) = 11300/2700 = 4.19.
Answer: The potential energy of a lead ball is 4.19 times higher.