At the start, a group of 10 skiers. Start one at a time, every 10 seconds.

At the start, a group of 10 skiers. Start one at a time, every 10 seconds. The speed of the skiers is approximately 3 m / s. What is the length of the chain?

n = 10.

t1 = 10 s.

V1 = 3 m / s.

L -?

The length of the chain L will be equal to the distance traveled by the first skier from the start to the exit of the last, tenth skier.

The first skier moved uniformly for a time t = t1 * (n – 1) with a speed V1.

The distance traveled by the first skier L is found by the formula: L = V1 * t = V1 * t1 * (n – 1).

L = 3 m / s * 10 s * (10 -1) = 270 m.

Answer: the length of the chain of skiers was L = 270 m.



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