At the surface of the water, the boy releases a stone, and it sinks to the bottom of the pond to a depth of H = 5 m.

At the surface of the water, the boy releases a stone, and it sinks to the bottom of the pond to a depth of H = 5 m. What amount of heat will be released when the stone falls if its mass is m = 500 g and its volume is V = 200 cm ^ 3?

To determine the value of the heat released during the fall of a stone in water, we will use the formula: Q = A = F * S = (Ft – Fa) * h = (m * g – ρw * g * V) * h = (m – ρw * V) * h * g.

Constants and variables: m is the mass of a stone falling in water (m = 500 g = 0.5 kg); ρw is the density of water (ρw = 1000 kg / m3); V is the volume of the stone (V = 200 cm3 = 200 * 10-6 m3); h is the distance from the surface of the water to the bottom of the pond (h = 5 m); g – acceleration due to gravity (g ≈ 10 m / s2).

Calculation: Q = (m – ρw * V) * h * g = (0.5 – 1000 * 200 * 10-6) * 5 * 10 = 15 J.

Answer: When a stone falls to the bottom of the pond, 15 J of heat will be released.