At what current density in the AgNO3 solution does the thickness of the released silver grow at a rate of 1 mm / h?

Data: VAg – growth rate of the silver layer (VAg = 1 mm / h = 2.7 (7) * 10-7 m / s).

Const: kAg – electrochemical equivalent of silver (kAg = 1.118 * 10-6 kg / C); ρAg is the density of silver (ρAg = 10500 kg / m3).

To find out the required current density in a silver nitrate solution, use the formula: j = I / S = m / (k * Δt) / S = m / (k * Δt * S) = ρAg * V / (k * Δt * S) = ρAg * S * h / (k * Δt * S) = ρAg * h / (k * Δt) = ρAg * VAg * Δt / (k * Δt) = ρAg * VAg / k.

Let’s calculate: j = ρAg * VAg / k = 10500 * 2.7 (7) * 10-7 / (1.118 * 10-6) = 2608.8 A / m2.

Answer: The required current density should be 2608.8 A / m2.