At what current strength is the magnetic field energy of a coil with an inductance of 0.6 H equal to 2, J?

To calculate the current in the used coil, apply the formula: W = L * I2 / 2, whence I = √ (2W / L).

Values of variables: W – magnetic field energy (W = 2 J); L is the inductance of the used coil (L = 0.6 H).

Let’s make a calculation: I = √ (2 * 2 / 0.6) = 2.58 A.

Answer: The amperage should be 2.58 A.



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