At what deformation of the spring, the stiffness of which is 250 N / m, will its energy become 500 J?

The potential energy of a deformed spring is determined by the formula:

Ep = k x ^ 2/2,

where k is the coefficient of stiffness (or simply stiffness) of the spring, k = 250 N / m;

x – the amount of deformation of the spring, m.

Thus, the required spring deformation:

x = (2Ep / k) ^ 1/2 = (2 × 500/250) ^ 1/2 = 2.00 m.

Answer: with a deformation of 2.00 m.

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