At what depth does the submarine move in the sea if the sea water presses with a force of 618 kN

At what depth does the submarine move in the sea if the sea water presses with a force of 618 kN on the cover of the exit hatch, which has an area of 3000 cm3?

Water pressure on the surface of the exit hatch cover:
P = F / S, where P is the value of the water pressure on the exit hatch cover (P = P hydr. = Ρ * g * h, where P is the hydrostatic pressure, ρ is the density of seawater (ρ = 1030 kg / m ^ 3) , g – acceleration due to gravity (we take g = 10 m / s ^ 2), h – immersion depth (m)), F – pressure force (F = 618 kN = 618 * 10 ^ 3 N), S – cover area ( S = 3000 cm ^ 2 = 0.3 m ^ 2).
ρ * g * h = F / S;
h = F / (S * ρ * g) = (618 * 10 ^ 3) / (0.3 * 10 * 1030) = 200 m.
Answer: the boat is moving at a depth of 200 m.