# At what depth in the pond is the pressure 2.5 times the normal atmospheric pressure?

**At what depth in the pond is the pressure 2.5 times the normal atmospheric pressure? density of water 1000kg / m3.**

Normal atmospheric pressure P = 760 mm. r.s. or 101325 Pa.

According to the condition, we have P = 2.5 * Patm

According to Pascal’s law:

The hydrostatic pressure inside the liquid at any depth does not depend on the shape of the vessel in which the liquid is located, and is equal to the product of the density of the liquid, the acceleration of gravity and the depth at which the pressure is determined:

P = ρ * g * h, where ρ is the density of the liquid, g is the free fall acceleration of a body raised above the Earth g = 9.8 m / s2, h is the depth of immersion in the liquid.

Let us express from this formula the depth of immersion:

h = P / (ρ * g)

In our case:

h = 2.5 * Patm / (ρ * g)

Substitute the numerical values and determine the depth:

h = 2.5 * Patm / (ρ * g) = 2.5 * 101325 / (1000 * 9.8) = 25.85 m.

Answer: at a depth of 25.85 meters.