At what depth in the pond is the pressure 2 times higher than the atmospheric pressure?

Given:

P = 101 kPa = 101000 Pascal – normal atmospheric pressure (approximate value);

ro = 1000 kg / m3 – water density.

It is required to determine h (meter) – at what depth the water pressure will be 2 times higher than atmospheric.

Since it is not indicated in the problem statement, we will consider the excess water pressure.

Then, we find the value of the water pressure:

P1 = 2 * P = 2 * 101000 = 202000 Pascal.

Knowing the water pressure, the depth can be determined from the following formula:

h = P / (ro * g) where g = 10 N / kg (approximate value);

h = 202000 / (1000 * 10);

h = 202,000 / 10,000 = 20.2 meters.

Answer: the water pressure will be 2 times the atmospheric pressure at a depth of 20.2 meters.