At what depth is a cork with an area of 15 cm2 in the bottom of a vessel with water, if a force of 29.4 N

At what depth is a cork with an area of 15 cm2 in the bottom of a vessel with water, if a force of 29.4 N acts on it from the side of the water. density of water 1000 kg * m3.

Data: S – plug area (S = 15 * 10-4 m2 (15 cm2)); F – force from the side of water (F = 29.4 N); ρw is the density of water in a vessel with a stopper (ρw = 1000 kg / m3).

Const: g – acceleration due to gravity (approx. G ≈ 9.8 m / s2).

To find out the depth at which the plug should be, consider the equality: F / S = P (pressure on the plug) = ρw * g * hx, whence we express: hx = F / (ρw * g * S).

Let’s perform the calculation: hx = F / (ρw * g * S) = 29.4 / (1000 * 9.8 * 15 * 10-4) = 2 m.

Answer: The plug is at a depth of 2 m.