At what depth is the pressure in the lake equal to 250 kPa?

The pressure of the liquid in the container is P = ρ * g * h, where ρ is the density of the liquid, g is the acceleration of gravity, h is the height of the container (depth). Let us express from this expression h = P / (ρ * g) We are dealing with a lake, since it is filled with water, then the density of the liquid is ρ = 1000 kg / m ^ 3. The acceleration value is constant and approximately equal to 10 m / s ^ 2. Therefore: h = 250,000 / (1000 * 10) = 25 m.