# At what distance from each other is it necessary to place two charges of 5 * 10-6 kl

At what distance from each other is it necessary to place two charges of 5 * 10-6 kl so that the interaction force in vacuum is equal to 0.5N

Initial data: F (force of interaction of charges) = 0.5 N; q1 = q2 (set value of charges) = 5 * 10-6 Cl.

Constants: k (coefficient of proportionality, for vacuum k = 9 * 109 N * m² / Kl²).

The distance at which it is necessary to place the given charges, we calculate by applying the Coulomb law:

F = k * | q1 | * | q2 | / r² and r = √ (k * q1 * q2 / F).

Let’s perform the calculation:

r = √ (9 * 109 * 5 * 10-6 * 5 * 10-6 / 0.5) = 0.67 m = 67 cm.

Answer: The given charges must be placed at a distance of 67 cm from each other.

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