At what height will the body be thrown up at a speed of 20 m / s?

Given:

v = 20 meters / second – the speed of a body thrown vertically upwards.

It is required to determine h (meter) – at what height the body will be.

Since the problem statement is not specified, we will not take into account the resistance force. Then, according to the law of conservation of energy:

Ekinetic (at the surface of the earth) = Epotential (at a height h);

m * v ^ 2/2 = m * g * h, where m is body mass, g = 10 Newton / kilogram (approximate value);

v ^ 2/2 = g * h;

h = v ^ 2 / (2 * g) = 20 ^ 2 / (2 * 10) = 400/20 = 40/2 = 20 meters.

Answer: the thrown body will be at a height of 20 meters.