At what minimum area of an ice floe 30 cm thick can it hold a person weighing 70 kg above water?

The force of normal ice pressure must balance the force of gravity of a person according to Newton’s third law.
Ice normal pressure force: N = m1g = // p1v1 // p1gv1
Human gravity: Ft = m2g
Let us equate formula (1) and (2), and express the volume:
P1gv = m2g
V-m2: p1 (fraction)
Here the volume is found by the formula: V = sh (4)
Substitute instead of volume (4) into formula (3), and express the area:
S = m2: p1 * H (fraction)
Substitute these values and find the area:
S = 70kg * m in 3rd power: 10m in 3rd power * 0.3 m (fraction) Approx = 0.2m squared
Answer: 0.2m squared