At what speed do the ends of the second and minute hands of a wrist watch move if their length

At what speed do the ends of the second and minute hands of a wrist watch move if their length of each hand is 12 mm?

R = 12 mm = 0.012 m.

t1 = 60 s.

t2 = 60 min = 3600 s.

V1 -?

V2 -?

In order to find the speed of the ends of the arrows V, it is necessary to divide the path L passed by the end of the arrow by the time of its passage t: V = L / t.

For one complete revolution, the second hand describes the circumference L = 2 * P * R, and the time of one complete revolution of the second hand is t1 = 60 s.

The speed of the second hand V1 will be determined by the formula: V1 = L / t1 = 2 * P * R / t1.

V1 = 2 * 3.14 * 0.012 m / 60 s = 0.001256 m / s.

In one complete revolution, the minute hand describes the circumference L = 2 * P * R, and the time of one complete revolution of the minute hand is t2 = 1 h = 60 min = 3600 s.

The speed of the minute hand V2 will be determined by the formula: V2 = L / t2 = 2 * P * R / t2.

V2 = 2 * 3.14 * 0.012 m / 3600 s = 0.00002 m / s.

Answer: the speed of the end of the second hand is V1 = 0.001256 m / s, the speed of the end of the minute hand is V2 = 0.00002 m / s.