At what speed does a diver diving from a 10-meter platform enter the water?

Initial data: h (height of the tower from which the diver jumped) = 10 m.

Reference data: g (acceleration due to gravity) ≈ 10 m / s2.

The speed at which the diver enters the water is determined using the law of conservation of energy: En = Ek and m * g * h = m * V ^ 2/2, whence V = √ (2 * g * h).

Let’s make the calculation: V = √ (2 * 10 * 10) = √200 = 14.14 m / s (50.9 km / h).

Answer: The diver will enter the water at a speed of 50.9 km / h.