At what speed does the electron move at an angle of 30 K by the lines of induction

At what speed does the electron move at an angle of 30 K by the lines of induction The induction of the magnetic field is 0.2 T and a force of 0.1 N acts on the electron.

Data of the problem: α (angle between the wind speed of the electron and the lines of induction) = 30º; B (value of magnetic field induction) = 0.2 T; Fl (value of the Lorentz force) = 0.1 N.

Reference values: q (electron charge) = -1.6 * 10 ^ -19 Cl.

We express the speed with which the electron should move from the formula: Fl = q * V * B * sinα, whence V = Fl / (q * B * sinα).

Let’s calculate: V = 0.1 / (1.6 * 10 ^ -19 * 0.2 * sin 30º) = 6.25 * 10 ^ 18 m / s.

Answer: The electron had to move at a speed of 6.25 * 10 ^ 18 m / s.