At what temperature is the gas if the average kinetic energy of the chaotic motion of its molecules

At what temperature is the gas if the average kinetic energy of the chaotic motion of its molecules is 20% higher than at 0 ° C?

Data: Ek2 (considered average kinetic energy of chaotic motion of molecules) = 1.2Ek1 (initial average kinetic energy); T1 (initial temperature of the taken gas) = 0 ºС (absolute temperature T1 = 273 K).

To determine the final temperature of the taken gas, we use the formula: Ek = 3/2 * k * T, whence 3/2 * k = Ek1 / T1 = Ek2 / T2 and T2 = Ek2 * T1 / Ek1.

Calculation: T2 = 1.2 * Ek1 * 273 / Ek1 = 1.2 * 273 = 327.6 K (54.6 ºС).

Answer: The taken gas is at a temperature of 54.6 ºС.



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