At what temperature is the gas if the average kinetic energy of the chaotic movement

At what temperature is the gas if the average kinetic energy of the chaotic movement of its molecules is 1.023 * 10 ^ -20

To determine at what temperature the taken gas is, we apply the formula: Ek = 3/2 * k * T, from where we express the temperature: T = 2Ek / 3k.

Values of constants and variables: k – Boltzmann’s constant (k = 1.38 * 10 ^ -23 J / K); Ek is the average kinetic energy of the chaotic movement of molecules (Ek = 1.023 * 10 ^ -20 J).

Let’s perform the calculation: T = 2 * 1.023 * 10 ^ -20 / (3 * 1.38 * 10 ^ -23) = 494.2 K (221.2 ºС).

Answer: The taken gas is at a temperature of 221.2 ºС.