At what temperature is the gas in a closed vessel if, when it is heated to 140 degrees C

At what temperature is the gas in a closed vessel if, when it is heated to 140 degrees C, the gas pressure has increased 1.5 times?

Data: isochoric process (closed vessel, V = const); ΔТ (temperature change) = 140 ºС; P2 (final gas pressure) = 1.5P1 (initial pressure).

We express the temperature at which the gas was with a closed vessel from the equation: P1 / T1 = P2 / T2.

P1 / T1 = 1.5P1 / (T1 + ΔТ).

1.5T1 = T1 + ΔT.

0.5T1 = ΔT = 140.

Т1 = 280 ºС.

Gas temperature after heating: T2 = Т1 + ΔТ = 280 + 140 = 420 ºС.

Answer: The initial gas temperature was 280 ºС; after heating, the gas is at a temperature of 420 ºС.



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