At what temperature was the gas if, with isobaric heating at 300 degrees Celsius, its volume increased 3 times.
| February 13, 2021 | education
Data: isobaric heating (P = const); ΔT (temperature change) = 300 K; V2 (final volume) = 3V1 (initial volume).
To determine the initial gas temperature, we use the proportion: V1 / T1 = V2 / T2.
V1 / T1 = 3V1 / (T1 + ΔT).
T1 + ΔT = 3T1.
ΔT = 2T1.
T1 = ΔT / 2 = 300/2 = 150 K.
Answer: Before isobaric heating, the gas was at a temperature of 150 K.
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