At what value of n is the value of expression 2n-6 5 times greater than the value of expression -4n + 1.

To find the value of the variable n at which the value of the expression 2n – 6 takes on a value 5 times greater than the value of the expression – 4n + 1, we compose and solve a linear equation with one variable.

2n – 6 = 5 (- 4n + 1);

Open the brackets on the right side of the equation using the distribution law of multiplication.

2n – 6 = – 20n + 5;

We transfer the terms without a variable to the right side of the equation, and to the left terms containing the variable n:

2n + 20n = 5 + 6;

22n = 11;

n = 11/22;

n = 1/2.

Answer: for n = 1/2, the conditions of the problem are satisfied.