At what value of x does the expressions 16-3x and 9x + 2 (x + 1) take equal expressions?

In order to find at what value of the variable x the expressions 16 – 3x and 9x + 2 (x + 1) take equal values, we compose and solve a linear equation with one variable.

So let’s equate these two expressions and get:

16 – 3x = 9x + 2 (x + 1);

We start solving the equation by opening the brackets on the right side of the equation:

16 – 3x = 9x + 2 * x + 2 * 1;

16 – 3x = 9x + 2x + 2;

We group the terms with and without variables in different parts of the equation:

-3x – 9x – 2x = 2 – 16;

x (-3 – 9 – 2) = -14;

-14x = -14;

x = -14: (-14);

x = 1.

Answer: x = 1.