At what voltage in the section of the circuit for 3 s, the work of the current 2 A will be equal to 6 J.

Given:

I = 2 Amperes – current strength in the circuit section;

t = 3 seconds – time interval;

A = 6 Joules – the work of the amperage during the time interval t.

It is required to find the voltage in the electrical circuit U (Volts).

According to the Joule-Lenz law:

A = I ^ 2 * R * t, hence:

R = A / (I ^ 2 * t) = 6 / (2 ^ 2 * 3) = 6 / (4 * 3) = 6/12 = 0.5 ohms.

Then, the voltage is:

U = I * R = 2 * 0.5 = 1 Volt.

Answer: the specified work will be done when the voltage on the circuit section is equal to 1 Volt.