Atmospheric pressure 740 mm Hg will this pressure in pascals be?

Given:

h = 740 millimeters of mercury;

g = 9.8 Newton / kilogram – acceleration of gravity (constant value near the earth’s surface);

ro = 13,500 kilograms per cubic meter – the density of mercury.

It is required to determine the pressure P (Pascal).

Let’s convert the units of measurement of length from millimeters to meters:

h = 740 mm = 740 * 10-3 = 0.74 meters.

Then a column of mercury with a height h will create a pressure equal to:

P = ro * g * h = 13500 * 9.8 * 0.74 = 132300 * 0.74 = 97902 Pascal.

Answer: the pressure of 740 millimeters of mercury corresponds to 97902 Pascal.