B triangle ABC AB = BC, BM median, angle ABC = 110deg. Find angle ABM.

Since, by condition, AB = BC, the triangle ABC is isosceles.

From vertex B we draw the median BM, which in an isosceles triangle will also be the height and bisector, since the triangles ABM and CBM are equal.

Then the angle ABM = ABC / 2 = 110/2 = 55.

Answer: Angle ABM is 55.



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