Barium hydroxide reacted with 294 g of sulfuric acid. Calculate the mass of the half-asleep

Barium hydroxide reacted with 294 g of sulfuric acid. Calculate the mass of the half-asleep sediment if the mass fraction of the reaction yield is 90%.

To solve the problem, let’s compose the equation:
1. Ba (OH) 2 + H2SO4 = BaSO4 + 2H2O – ion exchange reaction, obtained barium sulfate in the precipitate;
2. Calculations:
M (H2SO4) = 98 g / mol:
M (BaSO4) = 233.3 g / mol.
3. Determine the number of moles of acid:
Y (H2SO4) = m / M = 294/98 = 3 mol;
Y (BaSO4) = 3 mol since the amount of these substances according to the equation is 1 mol.
4. Find the theoretical mass of salt:
m (BaSO4) = Y * M = 3 * 233.3 = 699.9 g;
W = m (practical) / m (theoretical) * 100;
m (practical) = 0.90 * 699.9 = 629.9 g.
Answer: during the reaction, a precipitate of barium sulfate weighing 629.9 g is formed.