Barium nitrate, weighing 200 g, was added to copper sulfate to determine the mass of the sediment.

1. The interaction of copper sulfate with barium nitrate proceeds according to the equation:

CuSO4 + Ba (NO3) 2 = BaSO4 ↓ + Cu (NO3) 2;

2.Calculate the chemical amount of barium nitrate:

n (Ba (NO3) 2) = m (Ba (NO3) 2): M (Ba (NO3) 2);

M (Ba (NO3) 2) = 137 + 14 * 2 + 3 * 2 * 16 = 261 g / mol;

n (Ba (NO3) 2) = 200: 261 = 0.7663 mol;

3. Determine the amount and calculate the mass of barium sulfate:

n (BaSO4) = n (Ba (NO3) 2) = 0.7663 mol;

m (BaSO4) = n (BaSO4) * M (BaSO4);

M (BaSO4) = 137 + 32 + 4 * 16 = 233 g / mol;

m (BaSO4) = 0.7663 * 233 = 178.55 g.

Answer: 178.55 g.