Barlet salt decomposes according to the equation 2KCLO3 = 2KCLO3 + 3O2

Barlet salt decomposes according to the equation 2KCLO3 = 2KCLO3 + 3O2 What mass of this salt must be decomposed to obtain oxygen for filling with a 5L gas meter?

To solve the problem, let’s compose the reaction equation:
2KClO3 = 2KCl + 3O2 – decomposition reaction, gaseous oxygen is obtained;
M (KClO3) = 122.6 g / mol;
M (O2) = 32 g / mol;
Let us determine the amount of moles of oxygen, berthollet salt:
1 mole of gas occupies a volume of 22.4 liters. (with n. y);
X mol (O2) – 5 liters from here, X mol (O2) = 1 * 5 / 22.4 = 0.223 mol;
X mol (KClO3) – 0.223 mol (O2);
2 mol – 3 mol hence, X mol (KClO3) = 2 * 0.223 / 3 = 0.148 mol;
Let’s calculate the mass of Berthollet’s salt by the formula: m = Y * M;
m (KClO3) = 0.148 * 122.6 = 18.23 g.
Answer: the mass of berthollet salt is 18.23 g.



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