Based on AB of an isosceles triangle ABC, the segments AM = BN are plotted to prove that triangle ACM = triangle BCN.
| July 3, 2021 | education
Consider triangles ACM and BCN.
The sides AC and BC are equal from the fact that triangle ABC is isosceles.
The sides AM and BN are equal by the condition of the problem.
Angles CAB and CBA are equal again, since triangle ABC is isosceles.
Accordingly, triangles ACM and BCN are equal in terms of equality of two sides and the angle between them.
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