BC-chord of a circle with center O. Find the angle BOC if the angle BCO = 50 degrees.

In the OBC triangle, the sides of the OB and OS are equal, as are the radii of the circle O;
It follows that the angles VCO and CBO are equal to 50 degrees;
The sum of all the interior angles of a triangle is 180 degrees.
So the angle BOS = 180 – BCO – SVO.
180 – 50 – 50 = 80 (degrees) – VOS angle



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