BD is the bisector of angle D of trapezoid ABCD (AD \\ BC) and BD is perpendicular to AB

BD is the bisector of angle D of trapezoid ABCD (AD \\ BC) and BD is perpendicular to AB, angle A = 60 degrees. calculate the angles of the trapezoid.

Triangle ABD is rectangular, since, according to the condition, BD is perpendicular to AB, then the angle ADB = 180 – 90 – 60 = 30.

Since BD is the bisector of the ADC angle, the ADC angle = 2 * ADB = 2 * 30 = 60.

The sum of the angles of the trapezoid at its lateral side is 180, then the angle ABC = 180 – 60 = 120, DCB = 180 – 60 = 120.

Answer: The angles of the trapezoid are 60, 120, 120, 60.



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