Being under a pressure of 3 * 10 ^ 5Pa, the air expanded isobarically, and at the same time a work of 1.5 kJ

Being under a pressure of 3 * 10 ^ 5Pa, the air expanded isobarically, and at the same time a work of 1.5 kJ was performed. determine the increase in air volume.

Initial data: P (pressure at which the air was located) = 3 * 10 ^ 5 Pa; A (work of air at isobaric expansion) = 1.5 kJ (1500 J).

Since the air expanded isobarically, the increase in its volume can be determined by the formula: A = P * ΔV, whence ΔV = A / P.

Let’s make a calculation: ΔV = 1500 / (3 * 10 ^ 5) = 0.005 m3 (5 * 10 ^ -3 m3).

Answer:  the increase in air volume will be 5 * 10 ^ -3 m3.