Between acetic acid and KOH, CH3COOK weighing 7.2 grams is formed, find the mass with reacted alkali.

1. Let us write down the equation of the reaction between acetic acid and potassium hydroxide:

CH3COOH + KOH → CH3COOK + H2O;

2.Calculate the chemical amount of potassium acetate:

n (CH3COOK) = m (CH3COOK): M (CH3COOK);

M (CH3COOK) = 12 + 3 + 12 + 32 + 39 = 98 g / mol;

n (CH3COOK) = 7.2: 98 = 0.0735 mol;

3. Determine the amount of reacting alkali:

n (KOH) = n (CH3COOK) = 0.0735 mol;

4. find the mass of potassium hydroxide:

m (KOH) = n (KOH) * M (KOH);

M (KOH) = 39 + 16 + 1 = 56 g / mol;

m (KOH) = 0.0735 * 56 = 4.116 g.

Answer: 4.116 g.