Bisector AD is drawn in isosceles triangle ABC with base AC. Find the ADC angle if C = 50 degrees.
| February 17, 2021 | education
A = C = 50°;
A =BAD + DAC = 50°;
DAC = 50 / 2 = 25°;
ADC = 180° – C – DAC;
ADC = 180 – 50 – 25;
ADC = 105°.
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