Bisector AK is drawn in triangle ABC find the angles of the triangle if the angle BAK is 47

Bisector AK is drawn in triangle ABC find the angles of the triangle if the angle BAK is 47 degrees and the angle AKC is 103.

Given:
triangle ABC,
AK – bisector,
angle BAK = 47 degrees,
AKC angle = 103 degrees.
Find the degree measures of angle B, angle A, angle C -?
Solution:
1) Consider the triangle ABC.
angle A = 2 * 47 = 94 degrees;
2) Consider the triangle AKC. We know that the sum of the degree measures of any triangle is 180 degrees. Consequently:
angle С = 180 – (angle KAC + angle AKC);
angle C = 180 – (103 + 47);
angle C = 180 – 150;
angle C = 30 degrees;
3) Consider the AKB.
angle B = 180 – (94 + 30);
angle B = 180 – 124;
angle B = 56 degrees.
Answer: 94 degrees; 30 degrees; 56 degrees.