Bisector of angles A and B of triangle ABC intersect at point N Find ANB if A = 58 degrees and B = 96 degrees.

1. According to the condition of the problem, given: the bisectors of the angles A = 58 ° and B = 96 ° of the triangle ABC and the point of their intersection N.

2. In geometry it is known that:

a) the sum of all the angles of the triangle is 180 °;

b) the bisector divides the angle in half.

In the resulting triangle ANB, according to the bisector property

angle NAB = 1/2 angle A = 58 °: 2 = 29 °;

NBA angle = 1/2 angle B = 96 °: 2 = 48 °.

Hence the angle ANB = 180 ° – (29 ° + 48 °) = 180 ° – 77 ° = 103 °.

Answer: The ANB angle is 103 °.