BK is the height of the triangle ABC. Find the AC if AK-5 cm, KC-11 cm, angle A = 120 *.

Since the angle A = 120˚ (120˚ ˃ 90˚), the ABC triangle is obtuse. This means that the ВC height lies on the extension of the AC side, that is, the AK segment is part of the КC. Accordingly, the AC side is equal to:

AC = KС – AK;

AC = 11 – 5 = 6 cm.

Answer: AC = 6 cm.



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