Black-eyed (dominant homozygote) left-handed recessive gene married a blue-eyed (recessive gene) right-handed

Black-eyed (dominant homozygote) left-handed recessive gene married a blue-eyed (recessive gene) right-handed (dominant homozygote) male to identify the first offspring.

Let’s solve the genetic problem.

Given:

A – black eyes – a dominant sign.

a – blue eyes – a recessive sign.

B – right-handed – the dominant feature.

b – left-handed – a recessive trait.

♀ААbb – brown-eyed left-hander (dominant homozygote for the first trait, recessive homozygote for the second trait).

♂aaBB – blue-eyed right-hander (recessive homozygote for the first trait, dominant homozygote for the second trait).

Solution:

R: ♀AAbb x ♂aaBB.

Gametes: Ab, aB.

F1: AaBb.

Answer: The first offspring, like all subsequent ones, will be diheterozygous. The phenotype is brown-eyed right-handed.