Body weight 0.20 kg, and volume 210 cm square. Will this body drown in water?

Body weight 0.20 kg, and volume 210 cm square. Will this body drown in water? In kerosene? What is the density of the substance from which the body is made?

m = 0.2 kg.

g = 10 m / s2.

V = 210 cm3 = 0.00021 m3.

ρw = 1000 kg / m3.

ρк = 800 kg / m3.

ρт -?

The density of a substance ρт is called a scalar physical quantity that shows what mass a substance has taken in a volume of V = 1 m3.

The density of a substance ρт is determined by the formula: ρт = m / V.

ρт = 0.2 kg / 0.00021 m3 = 952 kg / m3.

Two forces act on a body immersed in a liquid: the force of gravity Ft, directed vertically downward, and the buoyancy force of Archimedes Farkh, directed vertically upward.

The force of gravity is determined by the formula: Ft = m * g, where m is the mass of the body, g is the acceleration of gravity.

Ft = 0.2 kg * 10 m / s2 = 2 N.

The buoyancy force of Archimedes is determined by the formula: Farch = ρ * g * V. Where ρ is the density of the liquid in which the body is immersed, g is the acceleration of gravity, V is the volume of the immersed part of the body in the liquid.

In water Farkh1 = 1000 kg / m3 * 10 m / s2 * 0.00021 m3 = 2.1 N.

In kerosene Farkh2 = 800 kg / m3 * 10 m / s2 * 0.00021 m3 = 1.68 N.

Farkh2 <Ft <Farkh1.

Answer: body density ρт = 952 kg / m3. The body will drown in kerosene and float in water.