Body weight in liquid The body weight, as determined by a spring dynamometer

Body weight in liquid The body weight, as determined by a spring dynamometer, in water is 2 times its weight in oil. Determine body density

Given:
ρ1 = 800kg / m ^ 3 – oil density;
ρ2 = 1000kg / m ^ 3 – water density;
P2 / P1 = 2;
Find: ρ -?
Body weight is
P = ρ * g * V,
Where
V – body volume,
g – acceleration of gravity;
If the body is completely immersed in liquid, its weight decreases due to the force of Archimedes:
P1 = P – F_A1 = ρ * g * V – ρ1 * g * V;
P2 = P – F_A2 = ρ * g * V – ρ2 * g * V;
Let’s write the relation:
P2 / P1 = (ρ * g * V – ρ2 * g * V) / (ρ * g * V – ρ1 * g * V) = (ρ – ρ2) / (ρ – ρ1) = 2;
ρ – ρ2 = 2 * ρ – 2 * ρ1;
From here we get:
ρ = 2 * ρ1 – ρ2 = 1600 – 1000 = 600kn / m ^ 3.